Integrand size = 12, antiderivative size = 33 \[ \int x \cos ^3\left (a+b x^2\right ) \, dx=\frac {\sin \left (a+b x^2\right )}{2 b}-\frac {\sin ^3\left (a+b x^2\right )}{6 b} \]
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Time = 0.04 (sec) , antiderivative size = 33, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.167, Rules used = {3461, 2713} \[ \int x \cos ^3\left (a+b x^2\right ) \, dx=\frac {\sin \left (a+b x^2\right )}{2 b}-\frac {\sin ^3\left (a+b x^2\right )}{6 b} \]
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Rule 2713
Rule 3461
Rubi steps \begin{align*} \text {integral}& = \frac {1}{2} \text {Subst}\left (\int \cos ^3(a+b x) \, dx,x,x^2\right ) \\ & = -\frac {\text {Subst}\left (\int \left (1-x^2\right ) \, dx,x,-\sin \left (a+b x^2\right )\right )}{2 b} \\ & = \frac {\sin \left (a+b x^2\right )}{2 b}-\frac {\sin ^3\left (a+b x^2\right )}{6 b} \\ \end{align*}
Time = 0.02 (sec) , antiderivative size = 33, normalized size of antiderivative = 1.00 \[ \int x \cos ^3\left (a+b x^2\right ) \, dx=\frac {\sin \left (a+b x^2\right )}{2 b}-\frac {\sin ^3\left (a+b x^2\right )}{6 b} \]
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Time = 1.25 (sec) , antiderivative size = 26, normalized size of antiderivative = 0.79
method | result | size |
derivativedivides | \(\frac {\left (2+\cos ^{2}\left (b \,x^{2}+a \right )\right ) \sin \left (b \,x^{2}+a \right )}{6 b}\) | \(26\) |
default | \(\frac {\left (2+\cos ^{2}\left (b \,x^{2}+a \right )\right ) \sin \left (b \,x^{2}+a \right )}{6 b}\) | \(26\) |
parallelrisch | \(\frac {9 \sin \left (b \,x^{2}+a \right )+\sin \left (3 b \,x^{2}+3 a \right )}{24 b}\) | \(28\) |
risch | \(\frac {3 \sin \left (b \,x^{2}+a \right )}{8 b}+\frac {\sin \left (3 b \,x^{2}+3 a \right )}{24 b}\) | \(31\) |
norman | \(\frac {\frac {\tan \left (\frac {a}{2}+\frac {b \,x^{2}}{2}\right )}{b}+\frac {\tan ^{5}\left (\frac {a}{2}+\frac {b \,x^{2}}{2}\right )}{b}+\frac {2 \left (\tan ^{3}\left (\frac {a}{2}+\frac {b \,x^{2}}{2}\right )\right )}{3 b}}{\left (1+\tan ^{2}\left (\frac {a}{2}+\frac {b \,x^{2}}{2}\right )\right )^{3}}\) | \(70\) |
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Time = 0.28 (sec) , antiderivative size = 25, normalized size of antiderivative = 0.76 \[ \int x \cos ^3\left (a+b x^2\right ) \, dx=\frac {{\left (\cos \left (b x^{2} + a\right )^{2} + 2\right )} \sin \left (b x^{2} + a\right )}{6 \, b} \]
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Time = 0.16 (sec) , antiderivative size = 44, normalized size of antiderivative = 1.33 \[ \int x \cos ^3\left (a+b x^2\right ) \, dx=\begin {cases} \frac {\sin ^{3}{\left (a + b x^{2} \right )}}{3 b} + \frac {\sin {\left (a + b x^{2} \right )} \cos ^{2}{\left (a + b x^{2} \right )}}{2 b} & \text {for}\: b \neq 0 \\\frac {x^{2} \cos ^{3}{\left (a \right )}}{2} & \text {otherwise} \end {cases} \]
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Time = 0.27 (sec) , antiderivative size = 27, normalized size of antiderivative = 0.82 \[ \int x \cos ^3\left (a+b x^2\right ) \, dx=\frac {\sin \left (3 \, b x^{2} + 3 \, a\right ) + 9 \, \sin \left (b x^{2} + a\right )}{24 \, b} \]
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Time = 0.29 (sec) , antiderivative size = 26, normalized size of antiderivative = 0.79 \[ \int x \cos ^3\left (a+b x^2\right ) \, dx=-\frac {\sin \left (b x^{2} + a\right )^{3} - 3 \, \sin \left (b x^{2} + a\right )}{6 \, b} \]
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Time = 13.87 (sec) , antiderivative size = 28, normalized size of antiderivative = 0.85 \[ \int x \cos ^3\left (a+b x^2\right ) \, dx=\frac {3\,\sin \left (b\,x^2+a\right )-{\sin \left (b\,x^2+a\right )}^3}{6\,b} \]
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